Question

Find the product using suitable identity
(3x+4y) (3x - 8y)​

Answer 1

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Answer 2

Answer:

Given,

(3x+4y) (3x - 8y)​.

To Find :

Product by suitable Identity.

Identity:

(z + a)(z - b) = $\sf z^{2} + (a - b) - ab$

Solution :

As,

(3x+4y) (3x - 8y)​ is in the form of above identity i.e (z + a)(z - b) = $\sf z^{2} + (a - b)z - ab$.

so,

(3x+4y) (3x - 8y)

= $\sf (3x)^{2} + (4y - 8y)3x - (4y*8y)$

= $\sf 9x^{2} + (-4y)3x- (4*y*8*y)$

=  $\sf 9x^{2} - 12xy - 32y^{2}$

$\sf\therefore$ (3x+4y) (3x - 8y) =  $\sf 9x^{2} - 12xy - 32y^{2}$

some Useful Algebraic Identities :

1) (x + a)(x + b) = $\sf x^{2} + (a + b)x + ab$

2) (x - a)(x - b) = $\sf x^{2} - (a + b)x + ab$

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