Find the product using suitable property 8225×999+8225
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Answered by
8
Answer:
Step-by-step explanation:
◆ Breaking 999 as ( 1000 - 1)
=> 8225× (1000 - 1) + 8225)
◆ Using Distributive Property of Multiplication over addition
=> 【( 8225 × 1000) - (8225 × 1) 】 + (8225)
=> [(8225000) - (8225)]+ 8225
=> [8225000 - 8225] + 8225
◆ OPENING THE BRACKETS
=> (8225000) + 8225 - 8225
◆ +8225 & -8225 will cancel out
=> 8225000
hope it helps u pls mark my answer as brainleist
Answered by
0
Answer:
muje nhi pata. #@|°=€{¶¥=€=€[€[}`}`}`°¥✓©✓©[®]}¢¶✓✓©=`}`}
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