Question

find the product [z^2+4] [z^2-5]

Answer 1

Answer:

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Step-by-step explanation:

z2−z=5−5i

4z2−4z=20−20i

4z2−4z+1=21−20i

(2z−1)2=(5−2i)2

2z−1=±(5−2i)

2z=1±(5−2i)

2z=1+5−2i

2z=6−2i

z=3−i

Real part=3

2z=1−5+2i

z=−2+i

Real part=-2

Product=3*-2=-6.

Answer 2

$(z^2+4)(z^2+5)\\\\= z^2 *z^2 + 5z^2 + 4z^2+ 20\\=z^4+9z^2+20$

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