find the products - algebra
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1
Answer:
8p^2×(p^3+p^2+p)+2yp(p^3+p^2+p)
8p^5+8p^4+8p^3+2yp^4+2yp^3+2yp^2
is the answer
Answered by
0
Answer:
8p5+32p4+32p6+24p2
Step-by-step explanation:
- 8pquare (p3+p2+p)+24p(p3+p2+p)
- 8p5+ 8p4+8p3+24p4+24p3+24p2
- add the number 8p4+24p4 and 8p3+24p3
- answer is 8p5+32p4+32p6+24p2
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