Math, asked by khushibhadauriya55, 8 months ago

Find the products of the following expressions.
(a) (3y + 5) and (6y + 8)
(b) (3x - 4y) and (8x - 6y)
(c) (5x^2 + 3y^2) and (2x ^2+ 4y^2?)
(d) (2x^2 + 14x) and (-x^2+1)

Answers

Answered by bhumi212
2

Answer:

(a)(3y+5) and (6y+8)

=3y+5+6y+8

=3y+6y+5+8

=9y+13

(b)(3x-4y) and (8x-6y)

=3x-4y+8x-6y

=3x+8x-4y-6y

=11x-10y

(c)(5x^2+3y^2) and (2x^2+4y^2)

=5x^2+3y^2+2x^2+4y^2

=5x^2+2x^2+3y^2+4y^2

=7x^2+7y^2

(d)(2x^2+14x) and (-x^2+1)

=2x^2+14x+(-x^2)+1

=2x^2+(-x^2)+14x+1

=2x^2-x^2+14x+1

=1x^2+14x+1

so this is ur answer ☺️

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