Find the products of the following using the identity (6+3w)^3
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Answer:
27w³ + 162w² + 324w + 216
Step-by-step explanation:
(a+b)³ = a³+b³+ 3ab(a+b)
(6+3w)³ = (6)³+(3w)³+(3×6×3w)(6+3w)
(6+3w)³ = 216 + 27w³ + 54w(6+3w)
(6+3w)³ = 216 + 27w³ + 324w + 162w²
(6+3w)³ = 27w³ + 162w² + 324w + 216
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