Question

find the profuct of the following pairs of monomials.
-4p,7pq
​

Answer 1

Answer:

Let us multiply the given monomials −4p and 7pq as shown below:

(−4p)×7pq

=(−4×7)×(p×p)×q

=(−28)×(p

1+1

)×q[∵a

x

×a

y

=a

x+y

]

=−28p

2

q

Hence, (−4p)×7pq=−28p

2q.