Question

Find the projection of the vector 2i-3j+6k on the vector i+2j+2k

Answer 1

Answer:

hope this answer in the above attachment helps you

Answer 2

Answer: $\frac{8}{3}$

Step-by-step explanation:

Given:- a=(2i-3j+6k)

            b=(i+2j+2k)

Concept:- Dot product of vectors and magnitude of vectors.

Solution:-

Projection of a on b = $\frac{a.b}{mod\ of\ b}$

                                 = $\frac{(2i-3j+6k).(i+2j+2k)}{\sqrt{1^{2} +2^{2}+2^{2} } }$

                                 = $\frac{2-6+12}{\sqrt{9} }$

                                = $\frac{8}{3}$

• Hence, the required projection is  $\frac{8}{3}$.

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