Question

find the projection of the vector ICAP + 3 J cap + 7 k cap on the vector 7 ICAP - 2 J cap + K cap​

Answer 1

Answer:

Projection of $\vec{a}$ on $\vec{b}$ is

$\frac{8}{3\sqrt{6}}$

Step-by-step explanation:

Formula used:

Projection of $\vec{a}$ on $\vec{b}$

$=\frac{\vec{a}.\vec{b}}{|\vec{b}|}$

Let,

$\vec{a}=\vec{i}+3\vec{j}+7\vec{k}$

$\vec{b}=7\vec{i}-2\vec{j}+\vec{k}$

$\vec{a}.\vec{b}=(1)(7)+(3)(-2)+(7)(1)$

$\vec{a}.\vec{b}=7-6+7$

$\vec{a}.\vec{b}=8$

$|\vec{b}|=\sqrt{7^2+(-2)^2+1^2}$

$|\vec{b}|=\sqrt{49+4+1}$

$|\vec{b}|=\sqrt{54}$

Now,

Projection of $\vec{a}$ on $\vec{b}$

$=\frac{\vec{a}.\vec{b}}{|\vec{b}|}$

$=\frac{8}{\sqrt{54}}$

$=\frac{8}{3\sqrt{6}}$

Answer 2

Answer:

answer of this question is....8/3 root 6....