Physics, asked by namazzisalmah9724, 11 months ago

Find the projection of vector a=2i-j+k along b=i+2j+2k

Answers

Answered by anchalsharma05
1

a.b=2-2+2=2. |b|=√1+4+4=√9=3. projection= 2/3

Answered by muscardinus
2

The projection of vector A on B is \dfrac{2}{3}.

Explanation:

Given that,

Vector A=2i-j+k

Vector B=i+2j+2k

We need to find the projection of vector A on B. Let it is given by c. It can be calculated as :

c=\dfrac{A{\cdot}B}{|b|}

c=\dfrac{2i-j+k {\cdot}i+2j+2k}{\sqrt{1^2+2^2+2^2}}

c=\dfrac{2-2+2}{3}

c=\dfrac{2}{3}

So, the projection of vector A on B is \dfrac{2}{3}. Hence, this is the required solution.

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