Math, asked by dhananjay2420, 11 months ago

find the proudect (2x-3y)(2x+3y)(4x²+9y²)​

Answers

Answered by mgssksinha
9

(2x-3y)(2x+3y)(4x^2 + 9y^2)

(2x^2- 3y^2)(4x^2 + 9y^2)

(4x^2 - 9y^2)(4x^2 + 9y^2)

Finally we get after factorizing

16x^4 - 81y^4

Answered by riya1504
7

By using identity-

(a+b)(a-b) = a² - b²

= (2x - 3y) (2x + 3y) (4x² + 9y²)

= (2x)² - (3y)² (4x² + 9y²)

= (4x² - 9y²) × (4x² + 9y²)

= (4x²)² - (9y²)²

= 16x⁴ - 81y⁴

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