Question

Find the pt on the x axis which is equidistant from the pts (-1,0),(5,0)

Answer 1

Solution :

Let us consider that the point on the x-axis is (x, 0).

By the given condition, distance of (x, 0) from (- 1, 0) point = distance of (x, 0) from (5, 0)

⇒ √{(x + 1)² + (0 - 0)²} = √{(x - 5)² + (0 - 0)²}

⇒ (x + 1)² = (x - 5)²

⇒ x² + 2x + 1 = x² - 10x + 25

⇒ 2x + 10x = 25 - 1

⇒ 12x = 24

⇒ x = 2

∴ the required point is (2, 0). (Ans.)