find the pythagoram triplet whose member is 63
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0
Answer:
THE GÎvĒÑ ÑØ ÎS = 63
WË KΠØW THÂT
2m,m²+1,m²-1
LET m be =8
2m =2*8=16
m²+1=8²+1= 65
m²-1=8²-1= 63
♦
♦ ♦ the no. is = 8,65,63.
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Answered by
0
Answer:
63
63 =6.3 × 1 0
6.3×1 0
63
Answer:
63
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