Question

find the Pythagoras triplet whose smallest number is 14

Answer 1

The formula is (2m)2,(m2 - 1)2,(m2 + 1)2
Smallest member = 2m = 14
2m = 14
m = 14/2 = 7
m2 - 1 = 72 - 1 = 49 - 1 = 48
m2 + 1 = 72 + 1 = 49 + 1 = 50
The required triplet is 14 , 48 and 50.



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Answer 2

Answer:

Given 14 is the smallest number in Pythagorean triplet

But we have for every number m>1, we have (2m,m  

2

−1,m  

2

+1) as a Pythagorean triplet

2m=14

m=14/2=7

Then m  

2

=49

m  

2

−1=49−1=48

m  

2

+1=49+1=50

Therefore the Pythagorean triple is =(2m,m  

2

−1,m  

2

+1)=(14,48,50)

HOPE THIS MAY HELP YOU...........................................