Find the Pythagoras triplets from among the following set of numbers 9, 24, 25
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. 32 = 9, 42 = 16, 52 = 25 Now, 9 + 16 = 25 ∴ 32 + 42 = 52 ∴ 3, 4 and 5 is a Pythagorean triplet. ii. 22 = 4, 42 = 16, 52 = 25 But, 4 + 16 ≠ 25 ∴ 22 + 42 ≠ 52 ∴ 2, 4 and 5 is not a Pythagorean triplet. iii. 42 = 16, 52 = 25, 62 = 36 But 16 + 25 ≠ 36 ∴ 42 + 52 ≠ 62 ∴ 4, 5 and 6 is not a
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Answer: No
Step-by-step explanation:
9 could be the base,
24 could be the height and
25 could be the hypotenuse
so 9^2+24^2=25^2 [a2+b2=c2]
657!=625[!= means not equal to]
So these aren't pythogorus triplets
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