Math, asked by bhaginath82, 3 days ago

find the Pythagoras triplets from following
1. 3,4,5
2. 2,4,5 ​

Answers

Answered by XxItzdivyaXx
1

Answer:

Answer is :- 3,4,5.

Step-by-step explanation:

As we know that,

Hypotenuse is the longest side of right - angled triangle.

By Pythagoras theorem,

\sf{Base}^{2}+{Perpendicular}^{2} = \sf{Height}^{2}

Here,

In Case I,

\sf{3}^2+{4}^2 = \sf{5}^2

\sf {9}+{16} = \sf{25}

\sf{25} = \sf{25}

Hence, It's a Pythagoras Triplet.

Now,

In Case II,

\sf{2}^2+{4}^2 =\sf{5}^2

\sf{4}+{16} = \sf{25}

\sf{20} \neq \sf{25}

Hence, It's not a Pythagoras Triplet.

\sf{@Divya}

Answered by aditya96088
1

Answer:

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1. 3,4 and 5 are Pythagoras triplet

Step-by-step explanation:

1. from Pythagoras theorem:

5² = 4² + 3²

25 = 16 + 9

25 = 25 , this is a Pythagoras triplet

2. from Pythagoras theorem:

5² = 4² + 2²

25 = 16 + 4

25 20 , this is not a Pythagoras triplet

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