Math, asked by Rounak8958, 11 months ago

Find the Pythagorean triple with the
following as one of its members.

(i) 10 (ii) 14 (iii) 16

Answers

Answered by Anonymous
11

(I). 6, 8, 10 forms an Pythagorean triplet.

6^2 + 8^2 = 10^2

= 36 + 64 = 100

100 = 100

(ii)14, 48, 50 form an Pythagorean triplet.

14^2 + 48^2 = 50^2

196 + 2304 = 2500

2500 = 2500

(iii) 16, 63, 65 form an Pythagorean triplet.

16^2 + 63^2 = 65^2

256 + 3969 = 4225

4225 = 4225

Similar questions