Question

Find the Pythagorean triples whose smalest
number is
18.
​

Answer 1

Answer:

Step-by-step explanation:

2M = 18

M = 18/2

M = 9(when we cancel 2/18)

M2(square)+1 = 9 2(square) + 1 = 82

M2(square) - 1 = 9 2(square) - 1 = 80

Therefore the required triplet 18,82,80

Answer 2

Answer:

2x,2x+1,2x-1

now,2x= 18

x=9

2x+1=18

2x=18+1

x=19/2

2x-1 =18

x=17/2

hope it helps