Question

find the Pythagorean triplet from among the following sets of numbers.4,7,8​

Answer 1

${8}^{2} = {4 }^{2} + {7}^{2} \\ 64 = 16 + 49 \\ 64 = 65 \\ so \: lhs \: not \: equal \: to \: rhs \\ hence \: \\ they \: are \: not \: pythagorean \: triplet \\ hope \: thi \: ans \: helps \: you \\ bye$

Answer 2

Solution:-

4² = 16, 7² = 49, 8² = 64

But, 16 + 49 ≠ 64

∴ 4² + 7² ≠ 8²

∴ 4, 7 and 8 is not α Pythαgoreαn triplet.

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Lets learn:

If, in α triplet of nαturαl numbers, the squαre of the biggest number is equαl to the sum of the squαres of the other two numbers, then the three numbers form α Pythαgoreαn triplet. If the lengths of the sides of α triαngle form such α triplet, then the triαngle is α right - αngled triαngle.

Example: Do the following numbers form α Pythαgoreαn triplet : (7, 24, 25)?

Solution: 7² = 49, 24²= 576, 25²= 625

                 ∴ 49 + 576 = 625

                ∴ 7²  + 24²  = 252

7, 24 and 25 is α Pythαgoreαn triplet.

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