Find the Pythagorean triplet, if its first member is
(i) 6 (ii) 12 (iii) 18 (iv) 30
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Answered by
7
Answer:
Pythagoras Theorem: Square of the length of the hypotenuse of a right angled triangle is the sum of the squares of the lengths of other two sides.
In right angled triangle, hypotenuse is the greatest side.
So, hypotenuse = 10
⇒(hypotenuse)
2
=10
2
=100
Now, 6
2
+8
2
=36+64=100
⇒10
2
=6
2
+8
2
Thus, 6, 8 and 10 are pythagorean triplets
Answered by
3
the answer is 6,8 and 10
this is your answer
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