Question

Find the Pythagorean triplet if one of its member is 18.​

Answer 1

Answer:

members of pythagorean triplet are in the form of 2m. m^2 -1, m^2 + 1

so, 2m=18

      m=18/2

         = 9

m^2-1

9^2 -1

81-1 = 80

m^2+1

9^2+1

81+1= 82

pythagoras triplets are: 18,80,82