Question

find the Pythagorean triplet if the greatest number is 65

Answer 1

[ pythagorean triplets are 2m, m²-1 & m²+1 ]

[ here, m²+1 is the greatest ]


$let \\ \: {m}^{2} + 1 = 65 \\ = {m}^{2} = 65 - 1 \\ = {m}^{2} = 64 \\ = m = \sqrt{64} \\ = m = 8$

1st no. = 2m = 2×8 = 16

2nd no. = m²-1 = (8)²-1 = 64-1 = 63

3rd no. = m²+1 = (8)²+1 = 64+1 = 65


♦ Pythagorean triplets are 16, 63 & 65

Answer 2

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