find the pythagorean triplet in which one number 12
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Answer:
(12, 35, 37)
Step-by-step explanation:
2m = 12
m = 6
Therefore,
m^2 -1
= 6^2 - 1
= 36 - 1
= 35
m^2 + 1
= 6^2 + 1
= 36 + 1
= 37
Therefore, 2m = 12, m^2 -1 = 35, m^2 +1 = 37
Hence, the triplet is (12, 35, 37)
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