Question

Find the Pythagorean triplet in which one number is 12

Answer 1

Step-by-step explanation:

5

$5^2 + 12^2 = 13^2 \\ (\sqrt{10}) ^{2} + (\sqrt{2})^{2} = 12 \\ (\sqrt{9})^{2} + (\sqrt{3})^{2} = 12$

hope that what u are looking for

i dont think there is no perfect square number like

$3 ^{2} + {4}^{2} = {5}^{2}$