find the pythagorean triplet in which the smallest number is 40.
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Answer: The Pythagorean triplet in which 40 is the smallest number is 399,401 and 40
Step-by-step explanation:
Let the smallest number be 2m
Then ,
2m = 40
m= 20
Now ,we know the formula for finding Pythagorean triplet
That is,
2m ,m^2-1 , m^2+1
Now,
2m= 40
m^2-1= 400-1=399
m^2+1=400+1=401
Hence solved..
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