find the pythagorean triplet one value is 17
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m^2+1=17
m^2=17-1
= 16
m=4×4 ( square root of 16)
=4
2m = 4*2=8
2m-1 = 2×4-1=7
2m+1=2×4+1=9
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m^2=17-1
= 16
m=4×4 ( square root of 16)
=4
2m = 4*2=8
2m-1 = 2×4-1=7
2m+1=2×4+1=9
this is the answer for your question if it is helpful for you Mark me as the brainliest
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