Question

find the pythagorean triplet such that 15 is one of its members..​

Answer 1

$\sf\huge\underline{Question:-}$

• Find Pythagorean triplet such that 15 is one of its members.

$\sf\huge\underline{Answer:-}$

$\sf\orange{Given \ number:-}$

• 15

$\sf\orange{To \ find:-}$

• Pythagorean triplet

$\sf\huge\underline{Solution:-}$

$= {m}^{2} - 1 = 15 = {m}^{2} = 16 = m = + 4$

${m}^{2} + 1 = 15 = {m}^{2} = 14$

$+ 4 \: and \: - 4 \: but \: - 4 \: is \: not \: a \: whole \: number$

$m = 4$

$2m \: \: \: \: \: \: \: {m}^{2} - 1$

$2(4) \: \: \: \: \: \: \: {4}^{2} - 1$

$8 \: \: \: \: \: 16 - 1 \: \: \: \: \: \: 16 +$

☞8 ; 15 ; 17

HENCE, the phythagorean triplets are 8 , 15 and 17.

_________________________

Answer 2

Answer:

answer is

Step-by-step explanation:

8,15,17.

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