Question

find​ the Pythagorean triplet whose. greatest member is 101


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Answer 1

Answer:

20, 99, 101

Step-by-step explanation:

2m, m²-1 and m²+1 are Pythagorean Triplets.

According to Question,

m²+1 = 101

=> m² = 101-1

=> m² = 100

=> m = √100

=> m = 10

2m = 2×10 = 20

m²-1 = 100-1 = 99

Hence, the Pythagorean Triplets are 20, 99 and 101.

Answer 2

Step-by-step explanation:

Pythagorean triplet has 3 positive integers of a, b, c such that.

General form: 2m, m2+1 ,m2 -1

m2+1= 101

m=10

m 2 - 1= 100 - 1 triplet is 20, 99 and 101