Math, asked by shrivasanushka13, 10 months ago

Find the Pythagorean triplet whose largest member is 29.

Answers

Answered by sowmiya261

2

Step-by-step explanation:

(2m,m^2+1,m^2-1)
2m=29

=29/2

=14.5

3.m^2+1

=14.5^2+1

=210.25+1

=211.25

4.m^2-1

=14.5^2-1

=210.25-1

=209.25

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