Question

find the Pythagorean triplet whose one member is 16

Answer 1

HEYA!!
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$= > a \: pythagorean \: triplet \: is \: represented \: by \: 2m \: \: \: m {}^{2} + 1 \: and \: m {}^{2} - 1$
Here ,

2m = 16

m = 8

Hence the other members are ,

$8 {}^{2} + 1 = 65 \\ \\ 8 {}^{2} - 1 = 63$
Hence the triplet is 16, 65 and 63 .

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