find the Pythagorean triplet whose one member is 65
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a Pythagorean triplet is represented by the 2m,m square+1 and m square-1
hence the largest number is m square+1
m square+1= 65
m square= 64
m= 8
2 m = 8× 2= 16
m square-1= 64-1=63
therefore answer is 65,16,63
hence the largest number is m square+1
m square+1= 65
m square= 64
m= 8
2 m = 8× 2= 16
m square-1= 64-1=63
therefore answer is 65,16,63
Anonymous:
hope it may help u
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