Find the pythagorean triplet whose one no is 97
Find the pythagorean triplet whose one no is 97
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Answer:
the Pythagorean triplet is : 65^2+ 72^2 = 97^2
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Answer:
Step-by-step explanation:
acording to formula 2n , 2n^2-1, 2n^2 + 1
or ab^2 + bc ^2 = ca^2
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