find the pythagorean triplet whose smallest member is 12
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Answer:
For every natural number m>2,(2m,m
2
−1,m
2
+1) is a pythagorean triplet and the smallest number is 2m
Given:2m=20⇒m=
2
20
=10
⇒m
2
−1=10
2
−1=100−1=99
and m
2
+1=10
2
+1=100+1=101
∴ The triplet is (20,99,101)
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