Question

find the Pythagorean triplet whose smallest member is 12

Answer 1

Solution :

For every natural number m>1m>1

(2m,m2−1,m2+1)(2m,m2−1,m2+1) is a Pythagorean triplet.

=> 2m=12

m=6

We get the triplet $

Answer : (12,35,37)

Answer 2

$hey$
For every natural number m>1m>1

(2m,m2−1,m2+1)(2m,m2−1,m2+1) is a Pythagorean triplet.

=> 2m=122m=12

m=6m=6

We get the triplet

2m = 2×6=12
${m}^{2} - 1 \\ = {6}^{2} - 1 \\ = 36 - 1 \\ = 35$
${m}^{2} + 1 \\ = {6}^{2} + 1 \\ = 36 + 1 \\ = 37$

Answer : (12,35,37)

HOPE IT HELPS YOU

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