find the pythagorean triplet whose smallest member is 20
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Pythagorean triplet = 2m , m square + 1 , m square - 1
2m = 20. So m = 20/2=10
10 square + 1 = 101
10 square - 1 = 99
So pythagorean triplets are 20 , 99 and 101
2m = 20. So m = 20/2=10
10 square + 1 = 101
10 square - 1 = 99
So pythagorean triplets are 20 , 99 and 101
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