find the pythagorean triplet whose smallest member is 22.
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As we know the formula to find pythogorean triplets is
2m, m×m+1, m×m-1.
So lets assume 22 as 2m
..so 22=2m
m=22÷2
m=11
m × m- 1 = 11 × 11- 1 = 120
m × m+ 1=11 × 11+1 = 122
So the pythogorean triplet is 22,120,122
Anonymous:
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