Question

Find the pythagorean triplet whose smallest member is 26

Answer 1

hey dear


here is your answer


Solution


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to find pythagoran triplet


( 2m, m^2 - 1 , m^2 +1 )


in this form we have to find


2m = 26

m = 26 / 2

m = 13



so


m^2 -1 = ( 13)^2 - 1

m^2 - 1 = 169 -1 = 168



then


m^2 + 1 = ( 13 )^2 +1

m^2 +1 = 169 +1 = 170.



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hence Pythagoran triplet are

( 26, 168, 170 )


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hope it helps

thank you

Answer 2

Hope it helps........