Question

Find the pythagorean triplet whose smallest number is 12.

Answer 1

Solution :

For every natural number m>1m>1

(2m,m2−1,m2+1)(2m,m2−1,m2+1) is a Pythagorean triplet.

=> 2m=122m=12

m=6m=6

We get the triplet $

Answer : (12,35,37)




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Answer 2

Answer:

12, 35, 37

Step-by-step explanation:

=> 2m = 12

=> m = 6

1st no.

= m^2 - 1

= 6^2 - 1

= 36 - 1

= 35

2nd no.

= m^2 + 1

= 6^2 + 1

= 36 + 1

= 37