Find the pythagorean triplet whose smallest number is 12.
Answers
Answered by
2
Solution :
For every natural number m>1m>1
(2m,m2−1,m2+1)(2m,m2−1,m2+1) is a Pythagorean triplet.
=> 2m=122m=12
m=6m=6
We get the triplet $
Answer : (12,35,37)
⭐here is ur answer
For every natural number m>1m>1
(2m,m2−1,m2+1)(2m,m2−1,m2+1) is a Pythagorean triplet.
=> 2m=122m=12
m=6m=6
We get the triplet $
Answer : (12,35,37)
⭐here is ur answer
coolway:
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Answered by
0
Answer:
12, 35, 37
Step-by-step explanation:
=> 2m = 12
=> m = 6
1st no.
= m^2 - 1
= 6^2 - 1
= 36 - 1
= 35
2nd no.
= m^2 + 1
= 6^2 + 1
= 36 + 1
= 37
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