Find the Pythagorean triplet whose smallest number is 16 . Find out the value.
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0
Answer:
Therefore, taking n=2 in (1.3), we find that (2×8,2×15,2×17)=(16,30,34) should also form a Pythagorean triplet and in (16,30,34), 16 is the smallest number.
Answered by
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Answer:
There are three numbers 2m,m^2-1\ and\ m^2+12m,m
2
−1 and m
2
+1 in a Pythagorean Triplet.
Here, 2m = 16 \Rightarrow m=\frac{16}{2}=8⇒m=
2
16
=8
Therefore, Second number \left(m^2-1\right)=\left(8\right)^2+1=64+1=65(m
2
−1)=(8)
2
+1=64+1=65
Hence, Pythagorean triplet is (16, 63, 65)
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