Question

Find the pythagorean triplet whose smallest number is 26

Answer 1

1st number is 26 then (formula is 2m,m^2-1,m^2+1)
2m =26
m=13 1st number

m^2 -1
169-1
168 2nd number
3rd number is 170 (m^2+1)=169+1=170