Question

find the Pythagorean triplets from the following set of a numbers 4m,7m,8m
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Answer 1

Main info :- We know that in the set of Pythagoras triplet the square of biggest number is equal the the square of other two number.

Given,

set of number = 4,7,8

The biggest number among these is 8

So,

${8}^{2 } = 64$

${7}^{2 } = 49$

${4}^{2} = 16$

Now , let us check

64 = 49 + 16

64 is not equal to 65 { 49+16 }

➪4,7,8 doesn't form a Pythagoras triplet

Hence , Verified ✅

Answer 2

Answer:

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