find the Pythagorean triplets of 17
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➡Or any natural number m > 1, 2 m, m2 – 1, m2 + 1 forms a Pythagorean Triplet.
Let us take m2+1=17m2=16m=4
⇒ value of m is an integer
So, this case is possible.
So we have,
2×4,42−1, 42+1=8,15,17
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The pythagorean triplets will be 17, 15 and 8..........
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