Question

find the pythagorean triplets of the numbers , the smallest of which is given below 14

Answer 1

14,48,50 is the triplet

Answer 2

$For \: every \: natural \: number \: m \gt 2 ;$

$( 2m, m^{2} - 1 , m^{2} + 1 ) \:is \: a$

$Pythagorean \:triplet . And \: the \: smallest$

$number \: is \: 2m$

$\blue {1 ) given \: 2m = 14 }$

$\implies m = \frac{14}{2}$

$\implies \green { m = 7 }$

$2) m^{2} - 1$

$= 7^{2} - 1$

$= 49 - 1$

$\green {= 48}$

$3 ) m^{2} + 1$

$= 7^{2} + 1$

$= 49 + 1$

$\green {= 50}$

Therefore.,

$\red{ Required \:Pythagorean \: Triplet }$

$\green { ( 14 , 48 , 50 ) }$

•••♪