Question

find the Pythagorean triplets whose smallest number is 18

Answer 1

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Here is your answer
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Let 2m = 18
m = 18/2
m = 9

IInd
m² - 1
= (9)² + 1
= 81 + 1
= 82

IIIrd
m² - 1
= (9)² - 1
= 81 - 1
= 80

Thus, 18, 80, 82 are Pythagorean triplets

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Answer 2

Answer:

The Pythagorean triplets are 18, 80, 82.

Step-by-step explanation:

Pythagorean Triplet:

• Pythagorean triplet consists of three numbers a, b, and c which should satisfy the equation a²+b² = c², where a and b are the base and perpendicular and c is the hypotenuse of the right angled triangle.
• The common notation for the three numbers are 2k, k²+1 and k²-1.

          Given one of the triplet as 18.

                 let 2k = 18

                         k = 18/2

                         k = 9

               Since k = 9            

       Substitute k = 9 in k²+1 and k²-1.

                   k²+1  = (9)²+1

                            = 81 + 1

                            = 82

                     k²-1 = (9)²-1

                            = 81 - 1

                            = 80

   Hence, the Pythagorean triplets are 18, 80, 82.

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