find the pythagorean whose member is 12
2m =12
answer accordingly to the above equation
plsssss answer with explanation
answer is 12, 35, 37
i don't know the step by step process
show the step by step explanation
Answers
Answered by
1
Explanation:
hey
For every natural number m>1m>1
2m,m2−1,m2+1)(2m,m2−1,m2+1 is a Pythagorean triplet.
=> 2m=122m=12
m=6m=6
We get the triplet
2m = 2×6=12
{m}^{2} - 1 \\ = {6}^{2} - 1 \\ = 36 - 1 \\ = 35
{m}^{2} + 1 \\ = {6}^{2} + 1 \\ = 36 + 1 \\ = 37
Answer : (12,35,37)
HOPE IT HELPS YOU
Answered by
1
Answer:
by using m²+1and m²-1 , fill m =6
Explanation:
2m=12
m=12*2=6
so first Pythagorean triplet,
2m=2(6)=12
second,
m²+1=6²+1=36+1=37
third,
m²-1=6²-1=36-1=35
hope it will help u...
remember to make it as brainlist answer...
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