Question

Find the Pythagoreantriplet whose smallest no is. 13

Answer 1

Hey there! ^_^

The general form of pythagorean triplet is (2m, m²-1,m²+1).

here 2m is the smallest number

Given smallest number =2m=13

m=13/2

Therefore the pythagorean triplet is ( 2*13/2,(13/2)²-1,(13/2)²+1)

(13,41.25,43.25) is the pythagorean triplet

In fractional form (13,165/4,173/4) is a pythagorean triplet

hope helped!

Answer 2

Hi ,

Pythagorean Triplet:

Three natural numbers m,

n and p are said to form

Pythagorean Triplet
( m , n , p ), if

m^2 + n^2 = p
For every natural number

m>1 , we have

( 2m , m^2 - 1 , m^2 + 1 ) as

a Pythagorean Triplet.

according to the problem ,

2m = 13

m = 13/2

m^2 - 1 = ( 13/2 )^2 - 1 = 169 /4- 1 = 165/4

m^2 + 1 = ( 13/2 )^2 + 1 = 169/4 + 1 = 173/4

Therefore ,

require triplet is ( 13 , 165/ 4 , 173/ 4 ) or

( 13 , 42.25 , 43.25 )

i hope this will useful to you.

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