Question

find the pythagoren triplets of the numbers the smallest of which is given below 14​

Answer 1

Step-by-step explanation:

pythagorean triplets will be in form of $m^{2}-1, 2m, m^{2}+1$

so if they have given any 1 even number then u should go through 2m

2m=14

m=$\frac{14}{2}$

m=7

So,

$m^{2}-1$= $7^{2}-1$

49-1

48

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$m^{2}+1$ = $7^{2}+1$

49+1

50

Answer:

So the Pythagorean triplets are 48,14,50

CHECKINGS:

u can check also

$50^{2}=14^{2}+48^{2}$

2500=196+2304

2500=2500