find the pythogorean triplet n=14
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Answer:
28, 195 and 197.
Step-by-step explanation:
Pythagoreon triplets are :
2n, n^2 - 1 and n^2 + 1.
Here
n = 14.
2n = 2 ☓ 14 = 28
n^2 = 14 ^2 = 196
➡️ n^2 - 1 = 196 - 1 = 195
➡️ n^2 + 1 = 196 + 1 = 197.
Now,
Pythagoreon triplet with n= 14 is :
28, 195, 197
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