Question

Find the Pythogorean triplet whose largest member
(2m, m²l, m²+1
lo
amxo​

Answer 1

Answer:

If we take m  

2

-1=12                  

Then m  

2

=12+1=13                        

Then the value of m will not be an integer  

So we try to take m  

2

+1=12 Again m  

2

=11 will not give an integer value for m  

So let us take 2m = 12

then m=6

Thus m  

2

−1=36−1=35  and   m  

2

+1=36+1=37

Therefore the required triplet is 12, 35, 37  

Note : All Phythagorean triplets may not be obtained using this form For example another triplet 5, 12, 13 also has 12 as a member

Step-by-step explanation: