Question

find the qadratic polynomial with zeroes 2and-1 by 3​

Answer 1

Step-by-step explanation:

The equation will be

x²−(-1/3+2)x+(2)(−1)=0

=x²−5/3x−2

Answer 2

Answer:

The zeroes of the polynomial are 2 and -1/3

Sum of the zeroes = 2 + -1/3

= 2 - 1/3 = 6 - 1/3 = 5/3

i. e., alpha + beta = 5/3

Product of zeroes = 2 × -1/3

= -2/3

i. e., alpha × beta = -2/3

Then the polynomial is of the form,

x² - (alpha + beta) × x + (alpha × beta ) = 0

x² - 5/3 × x + -2/3 = 0

x² - 5x/3 - 2/3 = 0

3x² - 5x - 2/3 = 0

3x² - 5x - 2 = 0

So the polynomial is

3x² - 5x - 2